Question
Answer
$$(3w+b-2)^2=b^2+6bw+9w^2-4b-12w+4$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(3w+b-2)^2& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}b^2+6bw+9w^2-4b-12w+4\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{3w+b-2}\right) $ by each term in $ \left( 3w+b-2\right) $. $$ \left( \color{blue}{3w+b-2}\right) \cdot \left( 3w+b-2\right) = 9w^2+3bw-6w+3bw+b^2-2b-6w-2b+4 $$ |
| ② | Combine like terms: $$ 9w^2+ \color{blue}{3bw} \color{red}{-6w} + \color{blue}{3bw} +b^2 \color{green}{-2b} \color{red}{-6w} \color{green}{-2b} +4 = b^2+ \color{blue}{6bw} +9w^2 \color{green}{-4b} \color{red}{-12w} +4 $$ |
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