Question
Answer
$$(3v-8)(2v+5)=6v^2-v-40$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(3v-8)(2v+5)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}6v^2+15v-16v-40 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}6v^2-v-40\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{3v-8}\right) $ by each term in $ \left( 2v+5\right) $. $$ \left( \color{blue}{3v-8}\right) \cdot \left( 2v+5\right) = 6v^2+15v-16v-40 $$ |
| ② | Combine like terms: $$ 6v^2+ \color{blue}{15v} \color{blue}{-16v} -40 = 6v^2 \color{blue}{-v} -40 $$ |
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