Question
Answer
$$(3+m)(4m+11)=4m^2+23m+33$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(3+m)(4m+11)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}12m+33+4m^2+11m \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}4m^2+23m+33\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{3+m}\right) $ by each term in $ \left( 4m+11\right) $. $$ \left( \color{blue}{3+m}\right) \cdot \left( 4m+11\right) = 12m+33+4m^2+11m $$ |
| ② | Combine like terms: $$ \color{blue}{12m} +33+4m^2+ \color{blue}{11m} = 4m^2+ \color{blue}{23m} +33 $$ |
This page was created using
Simplify polynomials calculator