Question
Answer
$$(3p^2+7p^4)(-2p+7)=-14p^5+49p^4-6p^3+21p^2$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(3p^2+7p^4)(-2p+7)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-6p^3+21p^2-14p^5+49p^4 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-14p^5+49p^4-6p^3+21p^2\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{3p^2+7p^4}\right) $ by each term in $ \left( -2p+7\right) $. $$ \left( \color{blue}{3p^2+7p^4}\right) \cdot \left( -2p+7\right) = -6p^3+21p^2-14p^5+49p^4 $$ |
| ② | Combine like terms: $$ -14p^5+49p^4-6p^3+21p^2 = -14p^5+49p^4-6p^3+21p^2 $$ |
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