Question
Answer
$$(3a-5)(2a-3)=6a^2-19a+15$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(3a-5)(2a-3)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}6a^2-9a-10a+15 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}6a^2-19a+15\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{3a-5}\right) $ by each term in $ \left( 2a-3\right) $. $$ \left( \color{blue}{3a-5}\right) \cdot \left( 2a-3\right) = 6a^2-9a-10a+15 $$ |
| ② | Combine like terms: $$ 6a^2 \color{blue}{-9a} \color{blue}{-10a} +15 = 6a^2 \color{blue}{-19a} +15 $$ |
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