Question
Answer
$$3-5n^2-(4-4n^2)=-n^2-1$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}3-5n^2-(4-4n^2)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}3-5n^2-4+4n^2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-n^2-1\end{aligned} $$ | |
| ① | Remove the parentheses by changing the sign of each term within them. $$ - \left( 4-4n^2 \right) = -4+4n^2 $$ |
| ② | Combine like terms: $$ \color{blue}{3} \color{red}{-5n^2} \color{blue}{-4} + \color{red}{4n^2} = \color{red}{-n^2} \color{blue}{-1} $$ |
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