Question
Answer
$$(2x+9)(3x-2)=6x^2+23x-18$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(2x+9)(3x-2)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}6x^2-4x+27x-18 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}6x^2+23x-18\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{2x+9}\right) $ by each term in $ \left( 3x-2\right) $. $$ \left( \color{blue}{2x+9}\right) \cdot \left( 3x-2\right) = 6x^2-4x+27x-18 $$ |
| ② | Combine like terms: $$ 6x^2 \color{blue}{-4x} + \color{blue}{27x} -18 = 6x^2+ \color{blue}{23x} -18 $$ |
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