Question
Answer
$$(2x+7)(x-9)=2x^2-11x-63$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(2x+7)(x-9)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}2x^2-18x+7x-63 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}2x^2-11x-63\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{2x+7}\right) $ by each term in $ \left( x-9\right) $. $$ \left( \color{blue}{2x+7}\right) \cdot \left( x-9\right) = 2x^2-18x+7x-63 $$ |
| ② | Combine like terms: $$ 2x^2 \color{blue}{-18x} + \color{blue}{7x} -63 = 2x^2 \color{blue}{-11x} -63 $$ |
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