Question
Answer
$$(2x+3)(x-5)=2x^2-7x-15$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(2x+3)(x-5)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}2x^2-10x+3x-15 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}2x^2-7x-15\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{2x+3}\right) $ by each term in $ \left( x-5\right) $. $$ \left( \color{blue}{2x+3}\right) \cdot \left( x-5\right) = 2x^2-10x+3x-15 $$ |
| ② | Combine like terms: $$ 2x^2 \color{blue}{-10x} + \color{blue}{3x} -15 = 2x^2 \color{blue}{-7x} -15 $$ |
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