Question
Answer
$$(2x-8)(4x^2+x-2)=8x^3-30x^2-12x+16$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(2x-8)(4x^2+x-2)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}8x^3+2x^2-4x-32x^2-8x+16 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}8x^3-30x^2-12x+16\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{2x-8}\right) $ by each term in $ \left( 4x^2+x-2\right) $. $$ \left( \color{blue}{2x-8}\right) \cdot \left( 4x^2+x-2\right) = 8x^3+2x^2-4x-32x^2-8x+16 $$ |
| ② | Combine like terms: $$ 8x^3+ \color{blue}{2x^2} \color{red}{-4x} \color{blue}{-32x^2} \color{red}{-8x} +16 = 8x^3 \color{blue}{-30x^2} \color{red}{-12x} +16 $$ |
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