Question
Answer
$$(2x-5)(x^2-4x+3)=2x^3-13x^2+26x-15$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(2x-5)(x^2-4x+3)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}2x^3-8x^2+6x-5x^2+20x-15 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}2x^3-13x^2+26x-15\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{2x-5}\right) $ by each term in $ \left( x^2-4x+3\right) $. $$ \left( \color{blue}{2x-5}\right) \cdot \left( x^2-4x+3\right) = 2x^3-8x^2+6x-5x^2+20x-15 $$ |
| ② | Combine like terms: $$ 2x^3 \color{blue}{-8x^2} + \color{red}{6x} \color{blue}{-5x^2} + \color{red}{20x} -15 = 2x^3 \color{blue}{-13x^2} + \color{red}{26x} -15 $$ |
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