Question
Answer
$$(2x-5)(4x-1)=8x^2-22x+5$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(2x-5)(4x-1)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}8x^2-2x-20x+5 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}8x^2-22x+5\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{2x-5}\right) $ by each term in $ \left( 4x-1\right) $. $$ \left( \color{blue}{2x-5}\right) \cdot \left( 4x-1\right) = 8x^2-2x-20x+5 $$ |
| ② | Combine like terms: $$ 8x^2 \color{blue}{-2x} \color{blue}{-20x} +5 = 8x^2 \color{blue}{-22x} +5 $$ |
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