Question
Answer
$$(2x-5)(2x^2-7x-4)=4x^3-24x^2+27x+20$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(2x-5)(2x^2-7x-4)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}4x^3-14x^2-8x-10x^2+35x+20 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}4x^3-24x^2+27x+20\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{2x-5}\right) $ by each term in $ \left( 2x^2-7x-4\right) $. $$ \left( \color{blue}{2x-5}\right) \cdot \left( 2x^2-7x-4\right) = 4x^3-14x^2-8x-10x^2+35x+20 $$ |
| ② | Combine like terms: $$ 4x^3 \color{blue}{-14x^2} \color{red}{-8x} \color{blue}{-10x^2} + \color{red}{35x} +20 = 4x^3 \color{blue}{-24x^2} + \color{red}{27x} +20 $$ |
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