Question
Answer
$$(2x-4)(7x-4)=14x^2-36x+16$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(2x-4)(7x-4)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}14x^2-8x-28x+16 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}14x^2-36x+16\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{2x-4}\right) $ by each term in $ \left( 7x-4\right) $. $$ \left( \color{blue}{2x-4}\right) \cdot \left( 7x-4\right) = 14x^2-8x-28x+16 $$ |
| ② | Combine like terms: $$ 14x^2 \color{blue}{-8x} \color{blue}{-28x} +16 = 14x^2 \color{blue}{-36x} +16 $$ |
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