Question
Answer
$$(2x-3)(4x^2-6x+9)=8x^3-24x^2+36x-27$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(2x-3)(4x^2-6x+9)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}8x^3-12x^2+18x-12x^2+18x-27 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}8x^3-24x^2+36x-27\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{2x-3}\right) $ by each term in $ \left( 4x^2-6x+9\right) $. $$ \left( \color{blue}{2x-3}\right) \cdot \left( 4x^2-6x+9\right) = 8x^3-12x^2+18x-12x^2+18x-27 $$ |
| ② | Combine like terms: $$ 8x^3 \color{blue}{-12x^2} + \color{red}{18x} \color{blue}{-12x^2} + \color{red}{18x} -27 = 8x^3 \color{blue}{-24x^2} + \color{red}{36x} -27 $$ |
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