Tap the blue circles to see an explanation.
| $$ \begin{aligned}(2x-3)(2x-3)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}4x^2-6x-6x+9 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}4x^2-12x+9\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{2x-3}\right) $ by each term in $ \left( 2x-3\right) $. $$ \left( \color{blue}{2x-3}\right) \cdot \left( 2x-3\right) = 4x^2-6x-6x+9 $$ |
| ② | Combine like terms: $$ 4x^2 \color{blue}{-6x} \color{blue}{-6x} +9 = 4x^2 \color{blue}{-12x} +9 $$ |