Question
Answer
$$(2x-11)(5x-3)=10x^2-61x+33$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(2x-11)(5x-3)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}10x^2-6x-55x+33 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}10x^2-61x+33\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{2x-11}\right) $ by each term in $ \left( 5x-3\right) $. $$ \left( \color{blue}{2x-11}\right) \cdot \left( 5x-3\right) = 10x^2-6x-55x+33 $$ |
| ② | Combine like terms: $$ 10x^2 \color{blue}{-6x} \color{blue}{-55x} +33 = 10x^2 \color{blue}{-61x} +33 $$ |
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