Question
Answer
$$(2x-1)(x^2-x-6)=2x^3-3x^2-11x+6$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(2x-1)(x^2-x-6)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}2x^3-2x^2-12x-x^2+x+6 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}2x^3-3x^2-11x+6\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{2x-1}\right) $ by each term in $ \left( x^2-x-6\right) $. $$ \left( \color{blue}{2x-1}\right) \cdot \left( x^2-x-6\right) = 2x^3-2x^2-12x-x^2+x+6 $$ |
| ② | Combine like terms: $$ 2x^3 \color{blue}{-2x^2} \color{red}{-12x} \color{blue}{-x^2} + \color{red}{x} +6 = 2x^3 \color{blue}{-3x^2} \color{red}{-11x} +6 $$ |
This page was created using
Simplify polynomials calculator