Question
Answer
$$(2x-1)(x+4)=2x^2+7x-4$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(2x-1)(x+4)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}2x^2+8x-x-4 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}2x^2+7x-4\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{2x-1}\right) $ by each term in $ \left( x+4\right) $. $$ \left( \color{blue}{2x-1}\right) \cdot \left( x+4\right) = 2x^2+8x-x-4 $$ |
| ② | Combine like terms: $$ 2x^2+ \color{blue}{8x} \color{blue}{-x} -4 = 2x^2+ \color{blue}{7x} -4 $$ |
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