Question
Answer
$$(2x-1)(8x-5)=16x^2-18x+5$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(2x-1)(8x-5)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}16x^2-10x-8x+5 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}16x^2-18x+5\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{2x-1}\right) $ by each term in $ \left( 8x-5\right) $. $$ \left( \color{blue}{2x-1}\right) \cdot \left( 8x-5\right) = 16x^2-10x-8x+5 $$ |
| ② | Combine like terms: $$ 16x^2 \color{blue}{-10x} \color{blue}{-8x} +5 = 16x^2 \color{blue}{-18x} +5 $$ |
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