Question
Answer
$$(2x-5)(5x+4)=10x^2-17x-20$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(2x-5)(5x+4)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}10x^2+8x-25x-20 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}10x^2-17x-20\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{2x-5}\right) $ by each term in $ \left( 5x+4\right) $. $$ \left( \color{blue}{2x-5}\right) \cdot \left( 5x+4\right) = 10x^2+8x-25x-20 $$ |
| ② | Combine like terms: $$ 10x^2+ \color{blue}{8x} \color{blue}{-25x} -20 = 10x^2 \color{blue}{-17x} -20 $$ |
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