Question
Answer
$$2x^2y-3x-(5x^2y+8)=-3x^2y-3x-8$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}2x^2y-3x-(5x^2y+8)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}2x^2y-3x-5x^2y-8 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-3x^2y-3x-8\end{aligned} $$ | |
| ① | Remove the parentheses by changing the sign of each term within them. $$ - \left( 5x^2y+8 \right) = -5x^2y-8 $$ |
| ② | Combine like terms: $$ \color{blue}{2x^2y} -3x \color{blue}{-5x^2y} -8 = \color{blue}{-3x^2y} -3x-8 $$ |
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