Question
Answer
$$2x^2+3x+2-(x^2-4x-1)=x^2+7x+3$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}2x^2+3x+2-(x^2-4x-1)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}2x^2+3x+2-x^2+4x+1 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}x^2+7x+3\end{aligned} $$ | |
| ① | Remove the parentheses by changing the sign of each term within them. $$ - \left( x^2-4x-1 \right) = -x^2+4x+1 $$ |
| ② | Combine like terms: $$ \color{blue}{2x^2} + \color{red}{3x} + \color{green}{2} \color{blue}{-x^2} + \color{red}{4x} + \color{green}{1} = \color{blue}{x^2} + \color{red}{7x} + \color{green}{3} $$ |
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