Question
Answer
$$(2x)^2+4y-x^2-y=3x^2+3y$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(2x)^2+4y-x^2-y& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}4x^2+4y-x^2-y \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}3x^2+3y\end{aligned} $$ | |
| ① | $$ \left( 2x \right)^2 = 2^2x^2 = 4x^2 $$ |
| ② | Combine like terms: $$ \color{blue}{4x^2} + \color{red}{4y} \color{blue}{-x^2} \color{red}{-y} = \color{blue}{3x^2} + \color{red}{3y} $$ |
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