| $$ \begin{aligned}2x(x-7)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}2x^2-14x\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{2x} $ by $ \left( x-7\right) $ $$ \color{blue}{2x} \cdot \left( x-7\right) = 2x^2-14x $$ |