Question
Answer
$$(2r-2)(-r-7)=-2r^2-12r+14$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(2r-2)(-r-7)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-2r^2-14r+2r+14 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-2r^2-12r+14\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{2r-2}\right) $ by each term in $ \left( -r-7\right) $. $$ \left( \color{blue}{2r-2}\right) \cdot \left( -r-7\right) = -2r^2-14r+2r+14 $$ |
| ② | Combine like terms: $$ -2r^2 \color{blue}{-14r} + \color{blue}{2r} +14 = -2r^2 \color{blue}{-12r} +14 $$ |
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