Question
Answer
$$(2+x)^2\cdot5=5x^2+20x+20$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(2+x)^2\cdot5& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}(4+4x+x^2)\cdot5 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}20+20x+5x^2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}5x^2+20x+20\end{aligned} $$ | |
| ① | Find $ \left(2+x\right)^2 $ using formula. $$ (A + B)^2 = \color{blue}{A^2} + 2 \cdot A \cdot B + \color{red}{B^2} $$where $ A = \color{blue}{ 2 } $ and $ B = \color{red}{ x }$. $$ \begin{aligned}\left(2+x\right)^2 = \color{blue}{2^2} +2 \cdot 2 \cdot x + \color{red}{x^2} = 4+4x+x^2\end{aligned} $$ |
| ② | $$ \left( \color{blue}{4+4x+x^2}\right) \cdot 5 = 20+20x+5x^2 $$ |
| ③ | Combine like terms: $$ 5x^2+20x+20 = 5x^2+20x+20 $$ |
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