Question
Answer
$$(2nx+1-n)(2mx+1-m)=4mnx^2-4mnx+mn+2mx+2nx-m-n+1$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(2nx+1-n)(2mx+1-m)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}4mnx^2-4mnx+mn+2mx+2nx-m-n+1\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{2nx+1-n}\right) $ by each term in $ \left( 2mx+1-m\right) $. $$ \left( \color{blue}{2nx+1-n}\right) \cdot \left( 2mx+1-m\right) = 4mnx^2+2nx-2mnx+2mx+1-m-2mnx-n+mn $$ |
| ② | Combine like terms: $$ 4mnx^2+2nx \color{blue}{-2mnx} +2mx+1-m \color{blue}{-2mnx} -n+mn = 4mnx^2 \color{blue}{-4mnx} +mn+2mx+2nx-m-n+1 $$ |
This page was created using
Simplify polynomials calculator