Question
Answer
$$(2m-3n)^2=4m^2-12mn+9n^2$$
Explanation
| $$ \begin{aligned}(2m-3n)^2& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}4m^2-12mn+9n^2\end{aligned} $$ | |
| ① | Find $ \left(2m-3n\right)^2 $ using formula. $$ (A - B)^2 = \color{blue}{A^2} - 2 \cdot A \cdot B + \color{red}{B^2} $$where $ A = \color{blue}{ 2m } $ and $ B = \color{red}{ 3n }$. $$ \begin{aligned}\left(2m-3n\right)^2 = \color{blue}{\left( 2m \right)^2} -2 \cdot 2m \cdot 3n + \color{red}{\left( 3n \right)^2} = 4m^2-12mn+9n^2\end{aligned} $$ |
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