Question
Answer
$$(2k+3)^2=4k^2+12k+9$$
Explanation
| $$ \begin{aligned}(2k+3)^2& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}4k^2+12k+9\end{aligned} $$ | |
| ① | Find $ \left(2k+3\right)^2 $ using formula. $$ (A + B)^2 = \color{blue}{A^2} + 2 \cdot A \cdot B + \color{red}{B^2} $$where $ A = \color{blue}{ 2k } $ and $ B = \color{red}{ 3 }$. $$ \begin{aligned}\left(2k+3\right)^2 = \color{blue}{\left( 2k \right)^2} +2 \cdot 2k \cdot 3 + \color{red}{3^2} = 4k^2+12k+9\end{aligned} $$ |
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