Question
Answer
$$(2a+1)^4=16a^4+32a^3+24a^2+8a+1$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(2a+1)^4& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} \htmlClass{explanationCircle explanationCircle4}{\textcircled {4}} } }}}16a^4+32a^3+24a^2+8a+1\end{aligned} $$ | |
| ① | $$ (2a+1)^4 = (2a+1)^2 \cdot (2a+1)^2 $$ |
| ② | Find $ \left(2a+1\right)^2 $ using formula. $$ (A + B)^2 = \color{blue}{A^2} + 2 \cdot A \cdot B + \color{red}{B^2} $$where $ A = \color{blue}{ 2a } $ and $ B = \color{red}{ 1 }$. $$ \begin{aligned}\left(2a+1\right)^2 = \color{blue}{\left( 2a \right)^2} +2 \cdot 2a \cdot 1 + \color{red}{1^2} = 4a^2+4a+1\end{aligned} $$ |
| ③ | Multiply each term of $ \left( \color{blue}{4a^2+4a+1}\right) $ by each term in $ \left( 4a^2+4a+1\right) $. $$ \left( \color{blue}{4a^2+4a+1}\right) \cdot \left( 4a^2+4a+1\right) = 16a^4+16a^3+4a^2+16a^3+16a^2+4a+4a^2+4a+1 $$ |
| ④ | Combine like terms: $$ 16a^4+ \color{blue}{16a^3} + \color{red}{4a^2} + \color{blue}{16a^3} + \color{green}{16a^2} + \color{orange}{4a} + \color{green}{4a^2} + \color{orange}{4a} +1 = \\ = 16a^4+ \color{blue}{32a^3} + \color{green}{24a^2} + \color{orange}{8a} +1 $$ |
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