Question
Answer
$$(2a-1)(3a-1)=6a^2-5a+1$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(2a-1)(3a-1)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}6a^2-2a-3a+1 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}6a^2-5a+1\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{2a-1}\right) $ by each term in $ \left( 3a-1\right) $. $$ \left( \color{blue}{2a-1}\right) \cdot \left( 3a-1\right) = 6a^2-2a-3a+1 $$ |
| ② | Combine like terms: $$ 6a^2 \color{blue}{-2a} \color{blue}{-3a} +1 = 6a^2 \color{blue}{-5a} +1 $$ |
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