Tap the blue circles to see an explanation.
| $$ \begin{aligned}(2-5t)^2& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}4-20t+25t^2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}25t^2-20t+4\end{aligned} $$ | |
| ① | Find $ \left(2-5t\right)^2 $ using formula. $$ (A - B)^2 = \color{blue}{A^2} - 2 \cdot A \cdot B + \color{red}{B^2} $$where $ A = \color{blue}{ 2 } $ and $ B = \color{red}{ 5t }$. $$ \begin{aligned}\left(2-5t\right)^2 = \color{blue}{2^2} -2 \cdot 2 \cdot 5t + \color{red}{\left( 5t \right)^2} = 4-20t+25t^2\end{aligned} $$ |
| ② | Combine like terms: $$ 25t^2-20t+4 = 25t^2-20t+4 $$ |