Tap the blue circles to see an explanation.
| $$ \begin{aligned}(2-3x)(2x+2)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}4x+4-6x^2-6x \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-6x^2-2x+4\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{2-3x}\right) $ by each term in $ \left( 2x+2\right) $. $$ \left( \color{blue}{2-3x}\right) \cdot \left( 2x+2\right) = 4x+4-6x^2-6x $$ |
| ② | Combine like terms: $$ \color{blue}{4x} +4-6x^2 \color{blue}{-6x} = -6x^2 \color{blue}{-2x} +4 $$ |