Question
Answer
$$(2-3x)(2x^2+3x+1)=-6x^3-5x^2+3x+2$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(2-3x)(2x^2+3x+1)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}4x^2+6x+2-6x^3-9x^2-3x \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-6x^3-5x^2+3x+2\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{2-3x}\right) $ by each term in $ \left( 2x^2+3x+1\right) $. $$ \left( \color{blue}{2-3x}\right) \cdot \left( 2x^2+3x+1\right) = 4x^2+6x+2-6x^3-9x^2-3x $$ |
| ② | Combine like terms: $$ \color{blue}{4x^2} + \color{red}{6x} +2-6x^3 \color{blue}{-9x^2} \color{red}{-3x} = -6x^3 \color{blue}{-5x^2} + \color{red}{3x} +2 $$ |
This page was created using
Simplify polynomials calculator