Tap the blue circles to see an explanation.
| $$ \begin{aligned}2(x-1)^4-40(x-1)^3+40(x-1)^2-32(x-1)+3& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} \htmlClass{explanationCircle explanationCircle4}{\textcircled {4}} } }}}2(x^4-4x^3+6x^2-4x+1)-40(x^3-3x^2+3x-1)+40(x^2-2x+1)-32(x-1)+3 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle5}{\textcircled {5}} } }}}2x^4-8x^3+12x^2-8x+2-(40x^3-120x^2+120x-40)+40x^2-80x+40-(32x-32)+3 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle6}{\textcircled {6}} } }}}2x^4-8x^3+12x^2-8x+2-40x^3+120x^2-120x+40+40x^2-80x+40-(32x-32)+3 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle7}{\textcircled {7}} } }}}2x^4-48x^3+132x^2-128x+42+40x^2-80x+40-(32x-32)+3 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle8}{\textcircled {8}} } }}}2x^4-48x^3+172x^2-208x+82-(32x-32)+3 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle9}{\textcircled {9}} } }}}2x^4-48x^3+172x^2-208x+82-32x+32+3 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle10}{\textcircled {10}} } }}}2x^4-48x^3+172x^2-240x+117\end{aligned} $$ | |
| ① | $$ (x-1)^4 = (x-1)^2 \cdot (x-1)^2 $$ |
| ② | Find $ \left(x-1\right)^2 $ using formula. $$ (A - B)^2 = \color{blue}{A^2} - 2 \cdot A \cdot B + \color{red}{B^2} $$where $ A = \color{blue}{ x } $ and $ B = \color{red}{ 1 }$. $$ \begin{aligned}\left(x-1\right)^2 = \color{blue}{x^2} -2 \cdot x \cdot 1 + \color{red}{1^2} = x^2-2x+1\end{aligned} $$ |
| ③ | Multiply each term of $ \left( \color{blue}{x^2-2x+1}\right) $ by each term in $ \left( x^2-2x+1\right) $. $$ \left( \color{blue}{x^2-2x+1}\right) \cdot \left( x^2-2x+1\right) = x^4-2x^3+x^2-2x^3+4x^2-2x+x^2-2x+1 $$ |
| ④ | Combine like terms: $$ x^4 \color{blue}{-2x^3} + \color{red}{x^2} \color{blue}{-2x^3} + \color{green}{4x^2} \color{orange}{-2x} + \color{green}{x^2} \color{orange}{-2x} +1 = x^4 \color{blue}{-4x^3} + \color{green}{6x^2} \color{orange}{-4x} +1 $$Find $ \left(x-1\right)^3 $ using formula $$ (A - B) = A^3 - 3A^2B + 3AB^2 - B^3 $$where $ A = x $ and $ B = 1 $. $$ \left(x-1\right)^3 = x^3-3 \cdot x^2 \cdot 1 + 3 \cdot x \cdot 1^2-1^3 = x^3-3x^2+3x-1 $$Find $ \left(x-1\right)^2 $ using formula. $$ (A - B)^2 = \color{blue}{A^2} - 2 \cdot A \cdot B + \color{red}{B^2} $$where $ A = \color{blue}{ x } $ and $ B = \color{red}{ 1 }$. $$ \begin{aligned}\left(x-1\right)^2 = \color{blue}{x^2} -2 \cdot x \cdot 1 + \color{red}{1^2} = x^2-2x+1\end{aligned} $$ |
| ⑤ | Multiply $ \color{blue}{2} $ by $ \left( x^4-4x^3+6x^2-4x+1\right) $ $$ \color{blue}{2} \cdot \left( x^4-4x^3+6x^2-4x+1\right) = 2x^4-8x^3+12x^2-8x+2 $$Multiply $ \color{blue}{40} $ by $ \left( x^3-3x^2+3x-1\right) $ $$ \color{blue}{40} \cdot \left( x^3-3x^2+3x-1\right) = 40x^3-120x^2+120x-40 $$Multiply $ \color{blue}{40} $ by $ \left( x^2-2x+1\right) $ $$ \color{blue}{40} \cdot \left( x^2-2x+1\right) = 40x^2-80x+40 $$Multiply $ \color{blue}{32} $ by $ \left( x-1\right) $ $$ \color{blue}{32} \cdot \left( x-1\right) = 32x-32 $$ |
| ⑥ | Remove the parentheses by changing the sign of each term within them. $$ - \left( 40x^3-120x^2+120x-40 \right) = -40x^3+120x^2-120x+40 $$ |
| ⑦ | Combine like terms: $$ 2x^4 \color{blue}{-8x^3} + \color{red}{12x^2} \color{green}{-8x} + \color{orange}{2} \color{blue}{-40x^3} + \color{red}{120x^2} \color{green}{-120x} + \color{orange}{40} = \\ = 2x^4 \color{blue}{-48x^3} + \color{red}{132x^2} \color{green}{-128x} + \color{orange}{42} $$ |
| ⑧ | Combine like terms: $$ 2x^4-48x^3+ \color{blue}{132x^2} \color{red}{-128x} + \color{green}{42} + \color{blue}{40x^2} \color{red}{-80x} + \color{green}{40} = \\ = 2x^4-48x^3+ \color{blue}{172x^2} \color{red}{-208x} + \color{green}{82} $$ |
| ⑨ | Remove the parentheses by changing the sign of each term within them. $$ - \left( 32x-32 \right) = -32x+32 $$ |
| ⑩ | Combine like terms: $$ 2x^4-48x^3+172x^2 \color{blue}{-208x} + \color{red}{82} \color{blue}{-32x} + \color{green}{32} + \color{green}{3} = 2x^4-48x^3+172x^2 \color{blue}{-240x} + \color{green}{117} $$ |