Question
Answer
$$18p^2+p-32-(40-13p^2)=31p^2+p-72$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}18p^2+p-32-(40-13p^2)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}18p^2+p-32-40+13p^2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}31p^2+p-72\end{aligned} $$ | |
| ① | Remove the parentheses by changing the sign of each term within them. $$ - \left( 40-13p^2 \right) = -40+13p^2 $$ |
| ② | Combine like terms: $$ \color{blue}{18p^2} +p \color{red}{-32} \color{red}{-40} + \color{blue}{13p^2} = \color{blue}{31p^2} +p \color{red}{-72} $$ |
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