Question
Answer
$$(12x+5y)(-4x+8y)=-48x^2+76xy+40y^2$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(12x+5y)(-4x+8y)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-48x^2+96xy-20xy+40y^2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-48x^2+76xy+40y^2\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{12x+5y}\right) $ by each term in $ \left( -4x+8y\right) $. $$ \left( \color{blue}{12x+5y}\right) \cdot \left( -4x+8y\right) = -48x^2+96xy-20xy+40y^2 $$ |
| ② | Combine like terms: $$ -48x^2+ \color{blue}{96xy} \color{blue}{-20xy} +40y^2 = -48x^2+ \color{blue}{76xy} +40y^2 $$ |
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