| $$ \begin{aligned}(11x^2+4)(11x-4)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}121x^3-44x^2+44x-16\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{11x^2+4}\right) $ by each term in $ \left( 11x-4\right) $. $$ \left( \color{blue}{11x^2+4}\right) \cdot \left( 11x-4\right) = 121x^3-44x^2+44x-16 $$ |