Question
Answer
$$11x^2+2-5x-(3+2x^2-5x)=9x^2-1$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}11x^2+2-5x-(3+2x^2-5x)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}11x^2+2-5x-3-2x^2+5x \xlongequal{ } \\[1 em] & \xlongequal{ }11x^2+2 -\cancel{5x}-3-2x^2+ \cancel{5x} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}9x^2-1\end{aligned} $$ | |
| ① | Remove the parentheses by changing the sign of each term within them. $$ - \left( 3+2x^2-5x \right) = -3-2x^2+5x $$ |
| ② | Combine like terms: $$ \color{blue}{11x^2} + \color{red}{2} \, \color{green}{ -\cancel{5x}} \, \color{red}{-3} \color{blue}{-2x^2} + \, \color{green}{ \cancel{5x}} \, = \color{blue}{9x^2} \color{red}{-1} $$ |
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