Question
Answer
$$11b^2-4b+7-(b^2+8b-9)=10b^2-12b+16$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}11b^2-4b+7-(b^2+8b-9)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}11b^2-4b+7-b^2-8b+9 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}10b^2-12b+16\end{aligned} $$ | |
| ① | Remove the parentheses by changing the sign of each term within them. $$ - \left( b^2+8b-9 \right) = -b^2-8b+9 $$ |
| ② | Combine like terms: $$ \color{blue}{11b^2} \color{red}{-4b} + \color{green}{7} \color{blue}{-b^2} \color{red}{-8b} + \color{green}{9} = \color{blue}{10b^2} \color{red}{-12b} + \color{green}{16} $$ |
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