Question
Answer
$$10x^2-4x+3-(7x^2-3x+13)=3x^2-x-10$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}10x^2-4x+3-(7x^2-3x+13)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}10x^2-4x+3-7x^2+3x-13 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}3x^2-x-10\end{aligned} $$ | |
| ① | Remove the parentheses by changing the sign of each term within them. $$ - \left( 7x^2-3x+13 \right) = -7x^2+3x-13 $$ |
| ② | Combine like terms: $$ \color{blue}{10x^2} \color{red}{-4x} + \color{green}{3} \color{blue}{-7x^2} + \color{red}{3x} \color{green}{-13} = \color{blue}{3x^2} \color{red}{-x} \color{green}{-10} $$ |
This page was created using
Simplify polynomials calculator