Question
Answer
$$(10.94-9.8x)^2=81x^2-180x+100$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(10.94-9.8x)^2& \xlongequal{ }(10.94-9x)^2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}100-180x+81x^2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}81x^2-180x+100\end{aligned} $$ | |
| ① | Find $ \left(10-9x\right)^2 $ using formula. $$ (A - B)^2 = \color{blue}{A^2} - 2 \cdot A \cdot B + \color{red}{B^2} $$where $ A = \color{blue}{ 10 } $ and $ B = \color{red}{ 9x }$. $$ \begin{aligned}\left(10-9x\right)^2 = \color{blue}{10^2} -2 \cdot 10 \cdot 9x + \color{red}{\left( 9x \right)^2} = 100-180x+81x^2\end{aligned} $$ |
| ② | Combine like terms: $$ 81x^2-180x+100 = 81x^2-180x+100 $$ |
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