Question
Answer
$$(10-3x)\cdot(4-5x)=15x^2-62x+40$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(10-3x)\cdot(4-5x)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}40-50x-12x+15x^2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}15x^2-62x+40\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{10-3x}\right) $ by each term in $ \left( 4-5x\right) $. $$ \left( \color{blue}{10-3x}\right) \cdot \left( 4-5x\right) = 40-50x-12x+15x^2 $$ |
| ② | Combine like terms: $$ 40 \color{blue}{-50x} \color{blue}{-12x} +15x^2 = 15x^2 \color{blue}{-62x} +40 $$ |
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