Question
Answer
$$-x^2+3x^3-2-(4x^2+3x)=3x^3-5x^2-3x-2$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}-x^2+3x^3-2-(4x^2+3x)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-x^2+3x^3-2-4x^2-3x \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}3x^3-5x^2-3x-2\end{aligned} $$ | |
| ① | Remove the parentheses by changing the sign of each term within them. $$ - \left( 4x^2+3x \right) = -4x^2-3x $$ |
| ② | Combine like terms: $$ \color{blue}{-x^2} +3x^3-2 \color{blue}{-4x^2} -3x = 3x^3 \color{blue}{-5x^2} -3x-2 $$ |
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