Question
Answer
$$(-5x^2+28x-141)(x+5)+700=-5x^3+3x^2-x-5$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(-5x^2+28x-141)(x+5)+700& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-5x^3-25x^2+28x^2+140x-141x-705+700 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-5x^3+3x^2-x-5\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{-5x^2+28x-141}\right) $ by each term in $ \left( x+5\right) $. $$ \left( \color{blue}{-5x^2+28x-141}\right) \cdot \left( x+5\right) = -5x^3-25x^2+28x^2+140x-141x-705 $$ |
| ② | Combine like terms: $$ -5x^3 \color{blue}{-25x^2} + \color{blue}{28x^2} + \color{red}{140x} \color{red}{-141x} \color{green}{-705} + \color{green}{700} = -5x^3+ \color{blue}{3x^2} \color{red}{-x} \color{green}{-5} $$ |
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