Question
Answer
$$-3x^2+x+5-(4x^2-2)=-7x^2+x+7$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}-3x^2+x+5-(4x^2-2)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-3x^2+x+5-4x^2+2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-7x^2+x+7\end{aligned} $$ | |
| ① | Remove the parentheses by changing the sign of each term within them. $$ - \left( 4x^2-2 \right) = -4x^2+2 $$ |
| ② | Combine like terms: $$ \color{blue}{-3x^2} +x+ \color{red}{5} \color{blue}{-4x^2} + \color{red}{2} = \color{blue}{-7x^2} +x+ \color{red}{7} $$ |
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