Question
Answer
$$(-3x)^2(3x+4y-1)=27x^3+36x^2y-9x^2$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(-3x)^2(3x+4y-1)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}9x^2(3x+4y-1) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}27x^3+36x^2y-9x^2\end{aligned} $$ | |
| ① | $$ \left( -3x \right)^2 = (-3)^2x^2 = 9x^2 $$ |
| ② | Multiply $ \color{blue}{9x^2} $ by $ \left( 3x+4y-1\right) $ $$ \color{blue}{9x^2} \cdot \left( 3x+4y-1\right) = 27x^3+36x^2y-9x^2 $$ |
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