Question
Answer
$$(-2-t)^3=-t^3-6t^2-12t-8$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(-2-t)^3& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-8-12t-6t^2-t^3 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-t^3-6t^2-12t-8\end{aligned} $$ | |
| ① | Find $ \left(-2-t\right)^3 $ using formula $$ (A - B) = A^3 - 3A^2B + 3AB^2 - B^3 $$where $ A = -2 $ and $ B = t $. $$ \left(-2-t\right)^3 = \left( -2 \right)^3-3 \cdot \left( -2 \right)^2 \cdot t + 3 \cdot \left( -2 \right) \cdot t^2-t^3 = -8-12t-6t^2-t^3 $$ |
| ② | Combine like terms: $$ -t^3-6t^2-12t-8 = -t^3-6t^2-12t-8 $$ |
This page was created using
Simplify polynomials calculator