| $$ \begin{aligned}(-160t+410)^2& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}25600t^2-131200t+168100\end{aligned} $$ | |
| ① | Find $ \left(-160t+410\right)^2 $ in two steps. S1: Change all signs inside bracket. S2: Apply formula $$ (A - B)^2 = \color{blue}{A^2} - 2 \cdot A \cdot B + \color{red}{B^2} $$where $ A = \color{blue}{ 160t } $ and $ B = \color{red}{ 410 }$. $$ \begin{aligned}\left(-160t+410\right)^2& \xlongequal{ S1 } \left(160t-410\right)^2 \xlongequal{ S2 } \color{blue}{\left( 160t \right)^2} -2 \cdot 160t \cdot 410 + \color{red}{410^2} = \\[1 em] & = 25600t^2-131200t+168100\end{aligned} $$ |